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Please show the titles of films and the types of market estimations.
CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR)
[SQL] SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID [/SQL]
Show the distinct director of films with market estimation in the year of 1995.
CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR)
[SQL] SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995 [/SQL]
What is the average number of cities of markets with low film market estimate bigger than 10000?
CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER)
[SQL] SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000 [/SQL]
Please list the countries and years of film market estimations.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR)
[SQL] SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID [/SQL]
Please list the years of film market estimations when the market is in country "Japan" in descending order.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR)
[SQL] SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC [/SQL]
List the studios of each film and the number of films produced by that studio.
CREATE TABLE film (Studio VARCHAR)
[SQL] SELECT Studio, COUNT(*) FROM film GROUP BY Studio [/SQL]
List the name of film studio that have the most number of films.
CREATE TABLE film (Studio VARCHAR)
[SQL] SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
List the names of studios that have at least two films.
CREATE TABLE film (Studio VARCHAR)
[SQL] SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2 [/SQL]
List the title of films that do not have any market estimation.
CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR)
[SQL] SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation) [/SQL]
Show the studios that have produced films with director "Nicholas Meyer" and "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
[SQL] SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill" [/SQL]
Find the titles and studios of the films that are produced by some film studios that contained the word "Universal".
CREATE TABLE film (title VARCHAR, Studio VARCHAR)
[SQL] SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%" [/SQL]
Show the studios that have not produced films with director "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
[SQL] SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill" [/SQL]
List the studios which average gross is above 4500000.
CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER)
[SQL] SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000 [/SQL]
What is the title of the film that has the highest high market estimation.
CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR)
[SQL] SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1 [/SQL]
What are the titles and directors of the films were never presented in China?
CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR)
[SQL] SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China') [/SQL]
How many calendar items do we have?
CREATE TABLE Ref_calendar (Id VARCHAR)
[SQL] SELECT COUNT(*) FROM Ref_calendar [/SQL]
Show all calendar dates and day Numbers.
CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR)
[SQL] SELECT calendar_date, day_Number FROM Ref_calendar [/SQL]
Show the number of document types.
CREATE TABLE Ref_document_types (Id VARCHAR)
[SQL] SELECT COUNT(*) FROM Ref_document_types [/SQL]
List all document type codes and document type names.
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
[SQL] SELECT document_type_code, document_type_name FROM Ref_document_types [/SQL]
What is the name and description for document type code RV?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR)
[SQL] SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV" [/SQL]
What is the document type code for document type "Paper"?
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
[SQL] SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper" [/SQL]
Show the number of documents with document type code CV or BK.
CREATE TABLE All_documents (document_type_code VARCHAR)
[SQL] SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK" [/SQL]
What is the date when the document "Marry CV" was stored?
CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR)
[SQL] SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV" [/SQL]
What is the day Number and date of all the documents?
CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR)
[SQL] SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date [/SQL]
What is the document type name for the document with name "How to read a book"?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR)
[SQL] SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book" [/SQL]
Show the number of locations.
CREATE TABLE Ref_locations (Id VARCHAR)
[SQL] SELECT COUNT(*) FROM Ref_locations [/SQL]
List all location codes and location names.
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
[SQL] SELECT location_code, location_name FROM Ref_locations [/SQL]
What are the name and description for location code x?
CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR)
[SQL] SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x" [/SQL]
What is the location code for the country "Canada"?
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
[SQL] SELECT location_code FROM Ref_locations WHERE location_name = "Canada" [/SQL]
How many roles are there?
CREATE TABLE ROLES (Id VARCHAR)
[SQL] SELECT COUNT(*) FROM ROLES [/SQL]
List all role codes, role names, and role descriptions.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR)
[SQL] SELECT role_code, role_name, role_description FROM ROLES [/SQL]
What are the name and description for role code "MG"?
CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
[SQL] SELECT role_name, role_description FROM ROLES WHERE role_code = "MG" [/SQL]
Show the description for role name "Proof Reader".
CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR)
[SQL] SELECT role_description FROM ROLES WHERE role_name = "Proof Reader" [/SQL]
Show the name, role code, and date of birth for the employee with name 'Armani'.
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR)
[SQL] SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani' [/SQL]
What is the id for the employee called Ebba?
CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR)
[SQL] SELECT employee_ID FROM Employees WHERE employee_name = "Ebba" [/SQL]
Show the names of all the employees with role "HR".
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
[SQL] SELECT employee_name FROM Employees WHERE role_code = "HR" [/SQL]
Show all role codes and the number of employees in each role.
CREATE TABLE Employees (role_code VARCHAR)
[SQL] SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code [/SQL]
What is the role code with the largest number of employees?
CREATE TABLE Employees (role_code VARCHAR)
[SQL] SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
Show all role codes with at least 3 employees.
CREATE TABLE Employees (role_code VARCHAR)
[SQL] SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3 [/SQL]
Show the role code with the least employees.
CREATE TABLE Employees (role_code VARCHAR)
[SQL] SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1 [/SQL]
What is the role name and role description for employee called Ebba?
CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
[SQL] SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba" [/SQL]
Show the names of employees with role name Editor.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
[SQL] SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor" [/SQL]
Show the employee ids for all employees with role name "Human Resource" or "Manager".
CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR)
[SQL] SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager" [/SQL]
What are the different location codes for documents?
CREATE TABLE Document_locations (location_code VARCHAR)
[SQL] SELECT DISTINCT location_code FROM Document_locations [/SQL]
Show the location name for document "Robin CV".
CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR)
[SQL] SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV" [/SQL]
Show the location code, the starting date and ending data in that location for all the documents.
CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR)
[SQL] SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations [/SQL]
What is "the date in location from" and "the date in location to" for the document with name "Robin CV"?
CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR)
[SQL] SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV" [/SQL]
Show the location codes and the number of documents in each location.
CREATE TABLE Document_locations (location_code VARCHAR)
[SQL] SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code [/SQL]
What is the location code with the most documents?
CREATE TABLE Document_locations (location_code VARCHAR)
[SQL] SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
Show the location codes with at least 3 documents.
CREATE TABLE Document_locations (location_code VARCHAR)
[SQL] SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3 [/SQL]
Show the location name and code with the least documents.
CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR)
[SQL] SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1 [/SQL]
What are the names of the employees who authorised the destruction and the employees who destroyed the corresponding documents?
CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR)
[SQL] SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id [/SQL]
Show the id of each employee and the number of document destruction authorised by that employee.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
[SQL] SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID [/SQL]
Show the employee ids and the number of documents destroyed by each employee.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
[SQL] SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID [/SQL]
Show the ids of the employees who don't authorize destruction for any document.
CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
[SQL] SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed [/SQL]
Show the ids of all employees who have authorized destruction.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
[SQL] SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed [/SQL]
Show the ids of all employees who have destroyed a document.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
[SQL] SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed [/SQL]
Show the ids of all employees who don't destroy any document.
CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR)
[SQL] SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed [/SQL]
Show the ids of all employees who have either destroyed a document or made an authorization to do this.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
[SQL] SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed [/SQL]
What are the names of all clubs?
CREATE TABLE club (clubname VARCHAR)
[SQL] SELECT clubname FROM club [/SQL]
How many students are there?
CREATE TABLE student (Id VARCHAR)
[SQL] SELECT COUNT(*) FROM student [/SQL]
What are the first names of all the students?
CREATE TABLE student (fname VARCHAR)
[SQL] SELECT DISTINCT fname FROM student [/SQL]
Find the last names of the members of the club "Bootup Baltimore".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" [/SQL]
Who are the members of the club named "Hopkins Student Enterprises"? Show the last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" [/SQL]
How many members does the club "Tennis Club" has?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" [/SQL]
Find the number of members of club "Pen and Paper Gaming".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming" [/SQL]
How many clubs does "Linda Smith" belong to?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith" [/SQL]
Find the number of clubs where "Tracy Kim" is a member.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim" [/SQL]
Find all the female members of club "Bootup Baltimore". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F" [/SQL]
Find all the male members of club "Hopkins Student Enterprises". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M" [/SQL]
Find all members of "Bootup Baltimore" whose major is "600". Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR)
[SQL] SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600" [/SQL]
Which club has the most members majoring in "600"?
CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
[SQL] SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
Find the name of the club that has the most female students.
CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
[SQL] SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
What is the description of the club named "Tennis Club"?
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
[SQL] SELECT clubdesc FROM club WHERE clubname = "Tennis Club" [/SQL]
Find the description of the club "Pen and Paper Gaming".
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
[SQL] SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming" [/SQL]
What is the location of the club named "Tennis Club"?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
[SQL] SELECT clublocation FROM club WHERE clubname = "Tennis Club" [/SQL]
Find the location of the club "Pen and Paper Gaming".
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
[SQL] SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming" [/SQL]
Where is the club "Hopkins Student Enterprises" located?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
[SQL] SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises" [/SQL]
Find the name of all the clubs at "AKW".
CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR)
[SQL] SELECT clubname FROM club WHERE clublocation = "AKW" [/SQL]
How many clubs are located at "HHH"?
CREATE TABLE club (clublocation VARCHAR)
[SQL] SELECT COUNT(*) FROM club WHERE clublocation = "HHH" [/SQL]
What are the first and last name of the president of the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
[SQL] SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President" [/SQL]
Who is the "CTO" of club "Hopkins Student Enterprises"? Show the first name and last name.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
[SQL] SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO" [/SQL]
How many different roles are there in the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR)
[SQL] SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore" [/SQL]
How many members of "Bootup Baltimore" are older than 18?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18 [/SQL]
How many members of club "Bootup Baltimore" are younger than 18?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18 [/SQL]
Find the names of all the clubs that have at least a member from the city with city code "BAL".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
[SQL] SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL" [/SQL]
Find the names of the clubs that have at least a member from the city with city code "HOU".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
[SQL] SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU" [/SQL]
How many clubs does the student named "Eric Tai" belong to?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
[SQL] SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai" [/SQL]
List the clubs having "Davis Steven" as a member.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
[SQL] SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven" [/SQL]
List the clubs that have at least a member with advisor "1121".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR)
[SQL] SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121 [/SQL]
What is the average age of the members of the club "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" [/SQL]
Find the average age of members of the club "Hopkins Student Enterprises".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" [/SQL]
Retrieve the average age of members of the club "Tennis Club".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
[SQL] SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" [/SQL]
What are the distinct grant amount for the grants where the documents were sent before '1986-08-26 20:49:27' and grant were ended after '1989-03-16 18:27:16'?
CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER)
[SQL] SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16' [/SQL]
List the project details of the project both producing patent and paper as outcomes.
CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR)
[SQL] SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent' [/SQL]
What is the total grant amount of the organisations described as research?
CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR)
[SQL] SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research' [/SQL]
List from which date and to which date these staff work: project staff of the project which hires the most staffs
CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR)
[SQL] SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader' [/SQL]
Find the organisation ids and details of the organisations which are involved in
CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR)
[SQL] SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000 [/SQL]
What is the organisation type and id of the organisation which has the most number of research staff?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)
[SQL] SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]
Which organisation type hires most research staff?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)
[SQL] SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1 [/SQL]